What is the equation of the line that passes through the point (-8,-8)and has a slope of 0
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Step-by-step explanation:
The slope-intercept form of a straight line is y=mx+c
In this case we have a point, (x,y) and the slope, m so all we need is a value of c.
Substitute into y=mx+c
−3=
4
5
(8)+c
−3=10+c
c=−13
The equation is : y=
4
5
x−13
Or you can use the formula for the situation where you have a point (x
1
,y
1
) and the slope, (m)→y−y
1
=m(x−x
1
)
y−(−3)=
4
5
(x−8)
y+3=
4
5
x−10
y=
4
5
x−13.
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