Math, asked by cook778147, 1 month ago

What is the equation of the line that passes through the point (-8,-8)and has a slope of 0

Answers

Answered by amruthaanayina
0

Step-by-step explanation:

The slope-intercept form of a straight line is y=mx+c

In this case we have a point, (x,y) and the slope, m so all we need is a value of c.

Substitute into y=mx+c

−3=

4

5

(8)+c

−3=10+c

c=−13

The equation is : y=

4

5

x−13

Or you can use the formula for the situation where you have a point (x

1

,y

1

) and the slope, (m)→y−y

1

=m(x−x

1

)

y−(−3)=

4

5

(x−8)

y+3=

4

5

x−10

y=

4

5

x−13.

Similar questions