What is the equation of the normal to the curve y = sin x at (0, 0)?
(a)x =0 (b) y=0 (c)x+y =0 (d)x-y=0
Answers
Answered by
3
Answer:
b) y = 0
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Answered by
2
Answer:
Solution:
A correct answer is an option (c)
Explanation:
Given that, y = sin x
Hence, dy/dx = cos x
Thus, the slope of the normal = (-1/cos x)x =0 = -1
Therefore, the equation of the normal is y-0 = -1(x-0) or x+y=0
Hence, the correct solution is option c.
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