Question

What is the equation of the quadratic function with a vertex at (2,-25) and an x-intercept at (7,0)?

Answer 1

Answer:

x^2 -4x-21

Step-by-step explanation:

Google: Vertex form of a quadratic equation is y=a(x-h)^2+k, where (h,k) is the vertex of the parabola.

use it with vertex(2,-25)

y=a(x-2)^2-25

now use the other info(7,0) substituting

0= a(5)^2-25

(5a)^2= 25

a=1

then the eq becomes

y= (x-2)^2-25

y= x^2 -4x-21