Physics, asked by pallavivmpallavivm20, 2 days ago

what is the equations of motion mention the meaning of symoboles​

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Answered by S21740ANUPRIYA01344
0

Answer:

Sorry I don't know please tell me

Answered by Anonymous
2

✡️ The equations of motion are mentioned below respectively:

\begin{gathered}\boxed{\begin{array}{c}\\ {\pmb{\sf{Three \: equation \: of \: motion}}} \\ \\ \sf \star \: v \: = u \: + at \\ \\ \sf \star \: s \: = ut + \: \dfrac{1}{2} \: at^2 \\ \\ \sf \star \: v^2 - u^2 \: = 2as\end{array}}\end{gathered}

Where, v denotes final velocity, u denotes initial velocity, a denotes acceleration, t denotes time taken and s denotes displacement or distance or height.

✡️ The above are the meaning of the symbols of equations of motion!

✡️ These equations of motion have particular names too. Let's see these relations name!

a. Velocity-time relation

b. Position-time relation

c. Position-velocity relation

Additional information:

Let's derive the first equation of motion graphically!

According to the graph...

⇢ AO = DC = u (Initial velocity)

⇢ AD = OC = t (Time)

⇢ EO = BC = v (Final velocity)

Now let's derive...

Considering a open object that moves under uniform acceleration where u is not equal to zero from the graph we are able to see that the initial velocity of the object that is at point A and then it increased to final values that is at point B in the time, the velocity change at the uniform rate acceleration. In the graph the perpendicular line BC and BE are drawn from point B on the time and validity axis respectively.

Firstly we can write BC as BD + DC. Now as BD have the velocity position and DC have the time position. Henceforth, we already know that

\begin{gathered}\tt \Rightarrow Acceleration \: = \dfrac{Change \: in \: velocity}{Time} \\ \\ \tt \Rightarrow a \: = \dfrac{Change \: in \: velocity}{Time} \\ \\ \tt \Rightarrow a \: = \dfrac{v-u}{t} \\ \\ \tt \Rightarrow a \: = \dfrac{BD}{t} \\ \\ \tt \Rightarrow at \: = BD\end{gathered}

As we write BD at the place of v-u henceforth,

\begin{gathered}\tt \Rightarrow v - u \: = at \\ \\ \tt \Rightarrow v = \: u \: + at \\ \\ {\pmb{\sf{Henceforth, \: derived!}}}\end{gathered}

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