Chemistry, asked by malaika1381, 2 months ago

What is the equilibrium constan of ionization
reaction for pure water?​

Answers

Answered by Anonymous
0

Answer:

The slight ionization of pure water is reflected in the small value of the equilibrium constant; at 25 °C. Thus, to three significant figures, Kw=1.01×10−14M at room temperature. Like any other equilibrium constant, Kw varies with temperature, ranging from 1.15×10−15 at 0°C to 4.99×10−13 at 100°C.

Explanation:

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Answered by AFAC
2

Explanation:

The slight ionization of pure water is reflected in the small value of the equilibrium constant; at 25 °C. Thus, to three significant figures, Kw=1.01×10−14M at room temperature. Like any other equilibrium constant, Kw varies with temperature, ranging from 1.15×10−15 at 0°C to 4.99×10−13 at 100°C.

Answered by AFAC
2

Explanation:

The slight ionization of pure water is reflected in the small value of the equilibrium constant; at 25 °C. Thus, to three significant figures, Kw=1.01×10−14M at room temperature. Like any other equilibrium constant, Kw varies with temperature, ranging from 1.15×10−15 at 0°C to 4.99×10−13 at 100°C.

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