Question

What is the equilibrium constant expression for the reaction
P4(s)+502(g)=P4010(s)?
(A) Kc=[P4010]/[P4][02]5
(B) KC=1/[O2]5
(C) Kc=[02]5
(D) Kc=[P4010]/5[P4][02]​

Answer 1

Explanation:

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