Question

What is the equivalent mass of KMNO4 in neutral and alkaline medium

Answer 1

Answer:

ANSWER

In acidic medium: MnO

4

−

+8H

+

+5e

−

→Mn

+2

+4H

2

O

In basic medium: MnO

4

−

+e

−

→MnO

4

2−

In neutral medium: MnO

4

−

+4H

+

+3e

−

→MnO

2

+2H

2

O

Equivalent mass is molecular mass divided by number of electrons gained.

In acidic medium, equivalent weight =

5

Molecularweight

In basic medium, equivalent weight =

1

Molecularweight

In neutal medium, equivalent weight =

3

Molecularweight

Ration of equivalent mass =

5

Molecularweight

:

1

Molecularweight

:

3

Molecularweight

Ratio of equivalent mass =3:15:5

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