What is the equivalent resistance if three resistances R1,R2,R3 are connected in series?
(ii) In the given circuit shows the combination of resistors
Calculate (i) Current through each resistor (ii) Total current in the circuit (iii) Total resistance in
the circuit.
Attachments:
Answers
Answered by
0
Answer:
If three resistances R1,R2,R3 are connected in series, the equivalent resistance will be 45 ohm.
(i) Current through 5 ohm = V/R = 12/5 = 2.4A
Current through 10 ohm = V/R = 12/10 = 1.2A
Current through 30 ohm = V/R = 12/30 = 0.4A
(ii) Total Current in the circuit = 2.4 + 1.2 + 0.4 = 4 A
(iii) Total Resistance in the circuit = (R1R2 + R2R3 + R3R1)/R1R2R3
= [5(10) + 10(30) +30(5)]/5(10)(30)
= [50 + 300 + 150]/1500
= 500/1500
= 1/3 ohm
Hope it heps you
Thank You
Similar questions