what is the equivalent resistance of the following
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Explanation:as we can we in the question the line connected to the common arc are in parallel in arrangement
Therefore 1+1/2*6=4
Now add the ssumm the resistance of the arc I.e.., 6
now we can see that the lines connected to the arc is in parallel in arrangement
I.e.., 1/4+1/6=5/12
So the resultant Req is 12/5
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