Question

What is the equivalent resistance of two resistance of 10 home's that are connected in parallel with each other

Answer 1

Given:-

• Resistance of Resistor ,R1 = 10 ohm
• Resistance of Resistor ,R2 = 10 ohm
• All Resistor are connected parallel.

To Find:-

• Equivalent resistance ,Req

Solution:-

According to the Question

It is given that the resistance of each resistor is 10 ohms & it is connected in parallel .

As we know that equivalent resistance in the parallel combination is calculated by the sum of reciprocal of its individual Resistors .

• 1/Req = 1/R1 + 1/R2

where,

• Req denote equivalent resistance
• R1 denote resistance of 1st Resistor
• R2 denote resistance of 2nd Resistor

Substitute the value we get

→ 1/Req = 1/10 + 1/10

→ 1/Req = 1+1/10

→ 1/Req = 2/10

→ 1/Req = 1/5

→ Req = 5 ohm

• Hence, the equivalent resistance in parallel combination is 5 ohm.

Answer 2

Answer:

Appropriate Question :-

• What is the equívalent resístance of two resístance of 10 ohm that are cónnected in párallel with each other.

Given :-

• The two resístance of 10 ohm that are connected in párallel with each other.

To Find :-

• What is the equívalent resístance.

Formula Used :-

$\clubsuit$ Equívalent Resístance for párallel connection :

$\mapsto \sf\boxed{\bold{\pink{\dfrac{1}{R_{eq}} =\: \dfrac{1}{R_1} + \dfrac{1}{R_2} + . . . . \dfrac{1}{R_n}}}}$

where,

• $\sf R_{eq}$ = Equívalent Resístance
• $\sf R_1$ = Resístance of resístors R₁
• $\sf R_2$ = Resístance of resístors R₂

Solution :-

Given :

• Resístance of resístors R₁ = 10 ohm
• Resístance of resístors R₂ = 10 ohm

According to the question by using the formula we get,

$\longrightarrow \sf \dfrac{1}{R_{eq}} =\: \dfrac{1}{10} + \dfrac{1}{10}$

$\longrightarrow \sf \dfrac{1}{R_{eq}} =\: \dfrac{1 + 1}{10}$

$\longrightarrow \sf \dfrac{1}{R_{eq}} =\: \dfrac{2}{10}$

$\longrightarrow \sf 2 \times R_{eq} =\: 10 \times 1$

$\longrightarrow \sf 2R_{eq} =\: 10$

$\longrightarrow \sf R_{eq} =\: \dfrac{\cancel{10}}{\cancel{2}}$

$\longrightarrow \sf R_{eq} =\: \dfrac{5}{1}$

$\longrightarrow \sf\bold{\red{R_{eq} =\: 5\: \Omega}}$

$\therefore$ The equívalent resístance is 5 Ω .

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EXTRA INFORMATION :-

$\clubsuit$ Equívalent Resístance for series connection :

$\mapsto \sf\boxed{\bold{\pink{R_{eq} =\: R_1 + R_2\: . . . .\: R_n}}}$

where,

• $\sf R_{eq}$ = Equívalent Resístance
• $\sf R_1$ = Resístance of resístors R₁
• $\sf R_2$ = Resístance of resístors R₂