what is the equivalent weiggt of M in Mo
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Let atomic mass of metal, M is A g/mol chemical formula of metal oxide is MO.
we know, oxidation state of O = -2
so, oxidation state of M = +2
so, equivalent weight of metal = A/2.....(1)
a/c to question,
The metal oxide MO contains 40% oxygen.
so, mass percentage of O = atomic mass of O/molecular mass of O × 100
or, 40 = 16/(A + 16) × 100
or, 1 = 40/(A + 16)
or, A = 24 g/mol , putting it in equation (1),
so, equivalent weight of metal = 24/2 = 12 g
hence, answer is 12
Explanation:
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