Question

what is the equivalent weight of H3PO3

Answer 1

Molecular weight of H3PO3 = 3×1 + 1×31 + 3×16

= 82 g

As we know Phosphorus acid is dibasic acid. So, it's basicity = 2

Therefore,

Equivalent mass = Molecular mass/2

= 82/2

= 41

Answer 2

The equivalent weight of $H_{3} PO_{3}$ is $E=\frac{M}{2}$.

Step-by-step explanation:

To find:

The equivalent weight of $H_{3} PO_{3}$.

Formula used:

Equivalent weight = Molecular weight/n factor

Solution:

$H_{3} PO_{3}$ is a dibasic acid, it can donate two hydrogen ions to a base in an acid-base reaction.

$H_{3} PO_{3}$ ⇒$2H^{+} +HPO_{3} ^{-}$

It has two basic elements.

So, the equivalent weight of $H_{3} PO_{3}$ is $E=\frac{M}{2}$.

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