Question

What is the equivalent weight of K2CR207 in acid medium equal to?
1) 1 /6 of molecular weight 2)1 /2of molecular weight 3)1 /5 of molecular weight
4) Molecular weight

Answer 1

Answer:

Explanation:

Answer:

1/6 times of molecular weight

Explanation:

Equivalent weight = Molecular weight / Change in Oxidation state

In acidic medium, the reaction of potassium Dichromate  with Sulphric acid is:

K2Cr2O7 + 14H + 6e----> 2K + 2Cr3+ 7H2O

|Change of oxidation state = 6

Hence Equivalent weight is equal to one sixth of molecular weight. Option 1