Question

What is the equivalent weight of kmno4 in alkaline medium?

Answer 1

So, equivalent weight = molar mass/ 3 = 87/3 = 29 gm/equivalent. As Mn7+ in KMnO4 changes to Mn2+ in acidic medium; it's equivalent weight becomes M/5. (where M is Molar mass of KMnO4.) Since mass of KMnO4 is 158, Equivalent Weight in acidic Medium is 31.4g.