What is the equivalent weight of LiC104 (Lithium perchlorate) Where M is its molar mass.
(A) M
(B) M/2
(C) M/3
(D) M/4
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Explanation:
Equivalent mass of an element=4
Vapour density of Cl−=59.25
To find:- Valency of element
Formula:- Let the compound be MClx
x is valency of M
(Refer to Image)
Molecular weight= 2× Vapour density....(i)
∴ Molecular weight of MClx=2×59.25=118.5....(ii)
Also, molecular weight
∴M+x×35.5=118.5....(iii) [M⟶ Atomic mass of M, x⟶ Number of atom of Cl]
∴M+35.5x=118.5....(iv)
We know,
Equivalent weight=ValencyAtomicmass....(v)
⇒4=xM....(Atomic mass=M from (iii))
∴M=4x....(vi)
Putting value of M in equation (iv)
⇒4x+35.5x=118.5
⇒39.5x=118.5
∴x=39.5118.5=3
∴ Valency of the element is 3.
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