What is the equivalent weight of phosphorus in compound P4O6
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Explanation:
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For the reaction 3A(g)+B(g)⇌2C(g), at the given temperature, K
c
=9.0. What must be the volume of the flask, if a mixture of 2.0 mol each of A, B and C exist in equilibrium?
Hard
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Correct option is A)
The equilibrium reaction is 3A(g)+B(g)⇌2C(g).
Let V be the volume of the flask.
The equilibrium number of moles of A,B and C are 2,2 and 2 respectively.
The equilibrium concentrations of A,B and C are
V
2
,
V
2
and
V
2
respectively.
The expression for the equilibrium constant is K
c
=
[A]
3
[B]
[C]
2
.
Substituting values in the above expression, we get
9.0=
(
V
2
)
3
(
V
2
)
(
V
2
)
2
.
Thus, V=6L.
Answer:
The equivalent weight of phosphorus in compound P4O6 is 10.3 units.
Explanation:
The charge of the given compound P₄O₆ is zero.
The charge of O is -2
∴ P₄* 6(-2) = 0
∴ P₄ = 12
∴ P =12/4 = 3
Therefore, the valency of P in P₄O₆ is 3.
We know that,
Equivalent weight=Molecular weight/Valency
Molecular weight of Phosphorous = 30.9
∴ Equivalent weight = 30.9/3 =10.3
Thus, the equivalent weight of phosphorus in compound P4O6 is 10.3 units.