Question

What is the equivalent weight of the metal in metal chloride if the chlorine content is 74.73% by mass?

Answer 1

Let the mass of the Metallic chloride be x .

Thus, Mass of the chlorine in the Metallic chloride = 74.73 % of Mass of the Metallic Chloride.
 = 74.73 % of x.
 = 0.7473x

Now, the Mass of the Metal in the chloride
 = Mass of the (Metallic Chloride - Chlorine in the Metallic Chloride.)
∴  Mass of the metal = x - 0.7473x
⇒  Mass of the Metal = 0.2527x


We know, Equivalent weight of the metal is given by the formula, 

Equivalent weight = (Mass of the Metal/Mass of the Chlorine) × Atomic Mass of the Chlorine.

Thus, Equivalent Weight of the Metal = (0.2527x/0.7473x) × 35.5
[Since, Atomic Mass of the Chlorine = 35.3]

Equivalent Weight of the Metal = 0.338 × 35.5
Therefore,  Equivalent weight of the Metal = 12.004

Hence, the Equivalent weight of the metal is 12.004.


Hope it helps.