What is the % error in measurement of time period of a pendulum, if maximum errors in measurements of length and ‘g' are 2% and 4%respectively?
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let a = 4 and b = 2
%error = % change
= a + b + ab / 100
= 4 + 2 + 4×2/ 100
= 4+ 2 + 8 / 100
= 6 + 0.08
= 6.08 %
therefore, % error in measurement of time period of a pendulum will be 6.08%.
%error = % change
= a + b + ab / 100
= 4 + 2 + 4×2/ 100
= 4+ 2 + 8 / 100
= 6 + 0.08
= 6.08 %
therefore, % error in measurement of time period of a pendulum will be 6.08%.
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