Physics, asked by neelam2453, 1 year ago

What is the escape speed from the surface of a planet whose radius is 5000 km, if the gravitational acceleration on its surface is 4.0 m/s21?

Answers

Answered by rishi7586
0
1/2*m v 2= GMm/R
g = GM/R2
GM/R = gR
V2 =2*g*R
V root 2gR = root (2*4*5000)=root 40000=200m/s

rishi7586: please brainlist
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