Question

What is the escape velocity of Chandrayaan 2 ?(along with the steps)

Answer 1

Answer:

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Answer 2

Answer:

The escape velocity for CHANDRAYAAN-2 is 11.2 km/s.

Explanation:

Escape velocity is the minimum velocity required by the body to remove itself from the earth gravitational field.

We know that the potential energy of the body is given by

$P.E.= \frac{GMm}{R+h}$.....................(1)

wher M=mass of the earth,m=mass of the Chandrayan - 2

h = height of the body from the earth surface.

We also know the K.E. of the body = $\frac{mv^{2} }{2}$...................(2)

where v = Escape velocity of the chandryan

From (1) and (2) we get

$v = \sqrt{\frac{2GM}{R+h} }$

Assume R+h=R

The escape velocity for CHANDRAYAAN-2 is 11.2 km/s.