Question

What is the expanded form of (3y – 2)³ ?

Answer 1

Answer:

(a-b)³=a³-b³+3a²b +3ab²

27y³- 8+3×(3y²)×2 + 3×3y×4

27y³- 8+6y²+36y

here is your answer

Answer 2

(3y – 2)³ = 27y³- 54y² + 36y - 8

Given :

(3y – 2)³

To find :

The expanded form

Formula :

(a - b)³ = a³ - 3a²b + 3ab² - b³

Solution :

Step 1 of 2 :

Write down the given expression

The given expression is

(3y – 2)³

Step 2 of 2 :

Find expanded form

We use the formula

(a - b)³ = a³ - 3a²b + 3ab² - b³

Thus we get

$\sf {(3y - 2)}^{3}$

$\sf = {(3y)}^{3} - 3 \times {(3y)}^{2} \times 2 + 3 \times 3y \times {2}^{2} - {2}^{3}$

$\sf = 27{y}^{3} - 3 \times 9 {y}^{2} \times 2 + 3 \times 3y \times 4 - 8$

$\sf = 27{y}^{3} - 54 {y}^{2} + 36y - 8$

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