what is the expanded form :(z-6)(z+2)
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z ( z + 2 ) -6 ( z + 2 )
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Here the identity that will be used is: (x+a)(x+b) = x² + (a+b)x +ab
So using that identity, we get:
z²+(-6+2)z+(-6)(2)
=z² - 4z -12
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