what is the expenditure to prepare a closed cuboidal tank of metal sheet of dimension 4m×3m×2m if the rate of metal sheet is 150 rupees per metre square
Answers
Answered by
11
Answer:
Total surface area of cuboid = 2(lb+bh+hl)
= 2(4x3+3x2+2x4)
= 2 (12+6+8)
=2 (26)
=52m^2
Therefore total expenditure = 52x150 = rupess7800.
Answered by
2
Answer:
₹7800
Step-by-step explanation:
Formula =
2(4×3+3×2+4×2)
2(26)
=52
Therefore , 150 × 52
= 7800
Ans = ₹7800
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