What is the explicit form of $\tau^{\alpha\beta}$ in the linearized Einstein field equations $\Box h^{\alpha\beta}=-16\pi\tau^{\alpha\beta}$?
Answers
Answered by
0
If we let hαβ=ηαβ−gαβ|det(g)|−−−−−−√hαβ=ηαβ−gαβ|det(g)| then, according to wikipedia, the Einstein Field Equations become
□hαβ=−16πταβ,◻hαβ=−16πταβ,
where □◻ is the d'Alembertian and ταβταβ is "the stress–energy tensor plus quadratic terms involving hαβhαβ." All I'm really asking for is what ταβταβis explicitly, and possibly a link to a source for the derivation of the above equations and how they are derived from the Einstein Field Equations.
□hαβ=−16πταβ,◻hαβ=−16πταβ,
where □◻ is the d'Alembertian and ταβταβ is "the stress–energy tensor plus quadratic terms involving hαβhαβ." All I'm really asking for is what ταβταβis explicitly, and possibly a link to a source for the derivation of the above equations and how they are derived from the Einstein Field Equations.
Answered by
0
If we let hαβ=ηαβ−gαβ|det(g)|−−−−−−√hαβ=ηαβ−gαβ|det(g)| then, according to wikipedia, the Einstein Field Equations become
□hαβ=−16πταβ,◻hαβ=−16πταβ,
where □◻ is the d'Alembertian and ταβταβ is "the stress–energy tensor plus quadratic terms involving hαβhαβ." All I'm really asking for is what ταβταβis explicitly, and possibly a link to a source for the derivation of the above equations and how they are derived from the Einstein Field Equations.
□hαβ=−16πταβ,◻hαβ=−16πταβ,
where □◻ is the d'Alembertian and ταβταβ is "the stress–energy tensor plus quadratic terms involving hαβhαβ." All I'm really asking for is what ταβταβis explicitly, and possibly a link to a source for the derivation of the above equations and how they are derived from the Einstein Field Equations.
Similar questions