Question

what is the external net force exerted on a 3.5 kg papaya, which is beiging pushed across a table and has an acclerations of 2.2 m /s2 to the left

Answer 1

Answer:

given = mass = 3.5Kg

            acceleration = 2.2.m/s

to find =  net force = ?

solution =

according to newtons second law,

F = ma

F = 3.5 X 2.2

F = 7.7 N

so the net force exerted on papaya is  7.7N