what is the external net force exerted on a 3.5 kg papaya, which is being pushed across a table and has an acceleration of 2.2 m/s to the left?
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please add all the given marks
excreted of 3.5 kg papaya pushed = 2.2
then you have to add the the following
3.5+2.2
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G=Force 3.5kg
acceleration 2.2 m/s2
R=mass
E=3.5kg.m/s2
2.2m/s2
S=3.5kg.m/s2
2.2kg.m/s2
A= 7.7N to the left
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