What is the external net force exerted on a 3.5 kg papaya,which is being pushed across a table and has an acceleration of 2.2 ms to the left
Answers
Answered by
55
Explanation:
External net force exerted on papaya. Therefore, the external net force exerted on papaya is 7.7 kg m/s².
Answered by
71
Given - Mass of papaya - 3.5 kg
Acceleration - 2.2m/s²
Find - Net force exerted
Solution - The three entities force, mass and acceleration are related to each other as Force= mass * acceleration.
Thus, keeping the values of mass and acceleration in formula to find the value of force.
Force = 3.5*2.2
Force = 7.7 Newton
Hence, external net force exerted is 7.7 Newton.
Force is defined as the influence that can change the motion of body.
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