What is the external net force exerted on a 3.5kg papaya, which is being push across a table and has an acceleration of 2.2 m/s² to the left?
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Answer:
the external force is 7.7N
Explanation:
Answer:
The external force is 7.7N
Explanation:
In this problem, we are to solve the external force exerted to accelerate the papaya across the table. Using the concept of Newton's first law of motion, we will be able to solve the external force.
Formula to use
F = ma
where
F is the force, the unit is in Newtons (N)
m is the mass, the unit is in kg
a is the acceleration, the unit is in m/s²
Given information
m = 3.5 kg
a = 2.2 m/s²
F = ?
Solving the problem
Let us solve the external force using the given formula
F = ma
Then, substitute the given data
F = (3.5 kg)(2.2 m/s²)
F = 7.7N
Therefore, the external force of the papaya is 7.7N
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