what is the factor of 2x^3-5x^2+16x+42
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Answer:
3125 is answer
Step-by-step explanation:
Given polynomial is of 3 rd degree so
We Wii have 3 factors
let f(x) = 2x^3 -5x^2–19x +42
Try x= +— 1 or x=+ -2
By remainder theorem if remainder of polynomial is 0 for that particular value x=a then we can say that (x--a ) is a FACTOR of f(x)
Put x=2 in f(x)
f(2) = 16--20-38+42 =0
(x-2) is afactor of f(x)
Dividing f(x) by (x-2) long method or synthetic method we get
(2x^2-x--21)
Factors of f(x) given are
(x-2) ( 2x^2-x--21)
Factors of
2x^2---x-21 =
= 2x^2 --7x+6x-21
=x(2x--7) +3(2x--7)
= (x+3)(2x--7)
So the factors of the given polynomial are
( x-2) (x+3) (2x-7)
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