what is the factor of 2x³+3x²-5x-6 using remainder theorem
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Answer:
2x3+3x2-5x-6
=2x3+2x2+x2+x -6x-6
=2x2(x+1)+x(x+1)-6(x+1)
=(x+1) (2x2+x-6)
=(x+1)(2x2+4x-3x-6)
=(x+1){2x(x+2)-3(x+2)}
=(x+1)(x+2)(2x-3)
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