Math, asked by kundan8950, 10 months ago

What is the factor of 64a²-16b²

Answers

Answered by Sudhir1188
13

ANSWER:

  • Factor of 64a²-16b² are (2a+b) , (2a-b) ,16.

GIVEN:

  • P(x) = 64a²-16b²

TO FIND:

  • Factor of 64a²-16b²

IDENTIFY USED:

  • a²-b² = (a+b)(a-b)

SOLUTION:

= 64a²-16b²

= 16(4a²-b²)

= 16[(2a)²-(b)²]

= 16(2a+b)(2a-b)

Factor of 64a²-16b² are (2a+b) , (2a-b) ,16.

NOTE:

Some important formulas:

(a+b)² = a²+b²+2ab

(a-b)² = a²+b²-2ab

(a+b)(a-b) = a²-b²

(a+b)³ = a³+b³+3ab(a+b)

(a-b)³ = a³-b³-3ab(a-b)

a³+b³ = (a+b)(a²+b²-ab)

a³-b³ = (a-b)(a²+b²+ab)

(a+b)² = (a-b)²+4ab

(a-b)² = (a+b)²-4ab

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