Question

What is the factor of (64y²-4) ÷ (4y-1)

Answer 1

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Answer 2

Given:

An algebraic expression (64y²-4) ÷ (4y-1).

To Find:

The factors or of the given expression are?

Solution:

The given problem can be solved using the concepts of algebra.

1. The identity that is used to solve the given problem is:

• $(a^2-b^2) = (a+b)(a-b)$

2. The given expression is (64y²-4) ÷ (4y-1). It can be also written as,

=> (64y²-4) ÷ (4y-1) = (4)(16y²-1)/(4y-1),

=> (16y²-1) = (4y+1)(4y-1),

=> (4)(16y²-1)/(4y-1) = (4)(4y+1)(4y-1)/(4y-1),

=> (64y²-4) /(4y-1) = 4(4y+1),

=>  (64y²-4) /(4y-1) = 16y + 4.

3. Factor = 16y + 4 (OR) 4(4y+1).

Therefore, the factor of (64y²-4) ÷ (4y-1) is 4(4y+1).