What is the factor of MnO4-1 in acidic medium
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+7 Answer: Be ( MnO4)----Ba^2+2MnO4
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2Mn^2
BA being most electropositive elements does not get reduced to Ba thus only MnO4 gets reduced to Mn^2 as it always does in acidic medium . (since compound has 2 atom of MN in it so it'n factor of given by in oxidation number per atom ) × ( number of atoms per molecule of formula unit of given reagent).
5×2 = 10 .
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