what is the factorisation for ab +bc+,ca
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Set a+b+c=x
So, we have (x−a)(x−b)(x−c)=x3−x2(a+b+c)+(ab+bc+ca)x−abc
Now, x3−x2(a+b+c)=x2(x−a+b+c¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯)=x2
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