what is the factorise by taking out the common factor of 18xy-12yz
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6y is answer
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Answer:
(i) 18xy – 12yz
= (2 × 3 × 3 × y × x) – (2 × 2 × 3 × y × z)
Taking out the common factors 2, 3, y, we get
= 2 × 3 × y (3x – 2z) = 6y (3x- 2z)
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