Question

What is the factorization of 121b4 − 49? (11b − 7)(11b − 7) (11b + 7)(11b − 7) (11b2 − 7)(11b2 − 7) (11b2 + 7)(11b2 − 7)

Answer 1

The factorization is (11b2+7)(11b2-7)

Answer 2

Answer:

121b⁴-49 = (11b²+7)(11b²-7)

Explanation:

We know the algebraic identity:

$\boxed { x^{2}-y^{2}=(x+y)(x-y)}$

Here ,

121b⁴ - 49

= (11b²)² - 7²

= (11b²+7)(11b²-7)

Therefore,

121b⁴ - 49 = (11b²+7)(11b²-7)

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