what is the factorization of 2x-3y
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Answered by
0
Answer:
Correct option is
B
2(2x−3y)(3y−4z)(2z−x)
C
6(2x−3y)(3y−4z)(2z−x)
D
3(2x−3y)(3y−4z)(2z−x)
(2x−3y)
3
+(3y−4z)
3
+(4z−2x)
3
The equation can be written in this way
We know, (a)
3
+(b)
3
+(c)
3
−3abc=(a+b+c)(a
2
+b
2
+c
2
−ab−bc−ca)
if a+b+c=0, then (a)
3
+(b)
3
+(c)
3
=3abc
Hence as we see, 2x−3y+3y−4z+4z−2x=0
(2x−3y)
3
+(3y−4z)
3
+(4z−2x)
3
=6(2x−3y)(3y−4z)(2z−x)
hence, option B,C,D are correct.
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