Math, asked by erviskkeherreria, 6 months ago

what is the factors of numerator and denominator and simplified form of 9m+9n over 9r-9s​

Answers

Answered by mathdude500
4

Answer:

 \frac{9m + 9n}{9r - 9s} \\  =  \frac{9(m + n)}{9(r - s)}  \\  =  \frac{m + n}{r - s}

Answered by akshay0222
1

Given,

\[F = \frac{{9m + 9n}}{{9r - 9s}}\]

Solution,

Know that a number that divides another number completely with no remainder is known as a factor of that number.

So, the factor  \[9m + 9n\] is

\[\begin{array}{l} \Rightarrow 9m + 9n\\ \Rightarrow 9\left( {m + n} \right)\end{array}\]

So, the factor \[9r - 9s\] is

\[\begin{array}{l} \Rightarrow 9r - 9s\\ \Rightarrow 9\left( {r - s} \right)\end{array}\]

Therefore, the simplified form is

\[\begin{array}{l} \Rightarrow \frac{{9m + 9n}}{{9r - 9s}}\\ \Rightarrow \frac{{9\left( {m + n} \right)}}{{9\left( {r - s} \right)}}\\ \Rightarrow \frac{{m + n}}{{r - s}}\end{array}\]

Hence, the factors of numerator and denominator is \[{9\left( {m + n} \right)}\] and \[{9\left( {r - s} \right)}\] and the simplified form is \[\frac{{m + n}}{{r - s}}.\]

Similar questions