Question

what is the false statement ?Sec2A-tan2A=1 , sec 2A=1+tan2A, sin 2A=1-cos2A ,cosec 2A+cot 2A=1 ​

Answer 1

answer is cosec²a + cot²a = 1

Step-by-step explanation:

AS WE KNOW

$\sin^{2} ( \alpha ) + \cos^{2}( \alpha ) = 1$

$\alpha = angle$

and then we divide whole equation by

$\sin^{2} \alpha \: \: we \: get$

$\frac{ \sin( \alpha ) }{ \sin( \alpha ) } + \frac{ \cos( \alpha ) }{ \sin( \alpha )} = \frac{1}{ \sin( \alpha ) }$

sina by sina is cut because it is same value