what is the farmula for median?
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l + { (n/2 - CF)/f } h
where l is the lower limit of the median class
n/2 is the half of the total frequency
CF- the cumulative frequency of the preceding class
f-frequency of the median class
h-height of the median class.
Please mark my answer as Brainliest.
where l is the lower limit of the median class
n/2 is the half of the total frequency
CF- the cumulative frequency of the preceding class
f-frequency of the median class
h-height of the median class.
Please mark my answer as Brainliest.
MalharKulkarni1:
it is wrong..the correct is L+[n/2-c.f]h/f
you're wrong
hey both are same.
yes
both same
Answered by
1
here me stands for median . I hope that you will understande this and it will help you.
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ok.i understand it..thnx
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