What is the fifth term of a number pattern that begins with 32 and adds 5?
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here first term is 32,
∴ a = 32
difference = d =5
fifth term is to be found ∴ n = 5
nth term is given by
tn= a +(n-1)d
∴t5=32 + (5-1)5
∴t5=32+4*5
∴t5= 32+20
∴t5 = 52
∴fifth term is 52
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