What is the final pressure when two gases at different pressure are mixed?
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3 answers · Chemistry
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The easiest way to work this out is from the Ideal Gas Law, PV=nRT. Assuming that they start at the same temperature, this is even easier because both R and T will be constants.
Lets make the first gas 1, the second gas 2 and the final mix f so that :
Pressure Gas 1 =P1, Volume Gas 1 = V1, Temperature Gas 1 = T1
Pressure Gas 2 =P2, Volume Gas 2 = V2, Temperature Gas 2 = T2
Pressure final mix =Pf, Volume final mix = Vf, Temperature final mix = Tf
then : P1V1/RT1+P2V2/RT2=PfVf/RTf
take out the constant R
P1V1/T1+P2V2/T2=PfVf/Tf
If T is different for each mix
Pf=(Tf*(P1V1/T1+P2V2/T2))/Vf
if T is constant (which I assume from your question)
P1V1+P2V2=PfVf
Pf=(P1V1+P2V2)/Vf
Hope this will help u... :-)
Best Answer
The easiest way to work this out is from the Ideal Gas Law, PV=nRT. Assuming that they start at the same temperature, this is even easier because both R and T will be constants.
Lets make the first gas 1, the second gas 2 and the final mix f so that :
Pressure Gas 1 =P1, Volume Gas 1 = V1, Temperature Gas 1 = T1
Pressure Gas 2 =P2, Volume Gas 2 = V2, Temperature Gas 2 = T2
Pressure final mix =Pf, Volume final mix = Vf, Temperature final mix = Tf
then : P1V1/RT1+P2V2/RT2=PfVf/RTf
take out the constant R
P1V1/T1+P2V2/T2=PfVf/Tf
If T is different for each mix
Pf=(Tf*(P1V1/T1+P2V2/T2))/Vf
if T is constant (which I assume from your question)
P1V1+P2V2=PfVf
Pf=(P1V1+P2V2)/Vf
Hope this will help u... :-)
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