Question

what is the final temperature if a sample of ammonia gas , initially at a pressure of 3.00 atm, a temperature of 500k, and a volume of 275L is changed to a volume of 200L and a pressure of 2.50atm
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Answer 1

Answer:

303K approx.

Explanation:

We know, (P1V1)/T1 = (P2V2)/T2

Given P1 = 3atm, P2= 2.50atm

V1= 275L, V2= 200L, T1= 500K, T2=? (to be found out)

Thus, (3x275)/500 = (2.5 x 200)/T2

           T2 = 10000/3 = 303.03K