Question

What is the final temperature when 20g of water at 80 degree is mixed with 40g ice at -10 degree Celsius

Answer 1

,............10degree celcius

Answer 2

Answer:

There is a formula to solve questions like the one you have asked. It goes like this:

Final temperature T =

$((m1 \times t1) \: + \: (m2 \times t2) ) \div (m1 + m2)$

where m1 and m2 represent mass of water at temperatures t1 and t2 respectively.

Therefore,

final temperature, T = (20*80+40*(-10))/(20+40)

= (1600-400)/(60)

=1200/60

= 20°C