Question

What is the final velocity of a proton that starts at +2.35 x 105 m/s, and is accelerated at

-1.10 x 1012 m/s2 for a period of 1.50 x 10-7s?​

Answer 1

2.35x105+(-1.10x1012)x(1.50x10^-7) [{([v=u+at])}]

246.74983302