Question

What is the first four terms of 7n-5

Answer 1

2,9,16,23

Step-by-step explanation:

If n=1,

7n-5=7×1-5=2

If n=2,

7n-5=7×2-5=9

If n=3,

7n-5=7×3-5=16

If n=4

7n-5=7×4-5=23

Answer 2

Step-by-step explanation:

$\huge{\underline{\underline{Given→}}}$

$Form\:of\:A.P=7n-5$

$\huge{\underline{\underline{To\:Find→}}}$

→First four terms of the A.P

$\huge{\underline{\underline{Answer→}}}$

☆Form=7n-5

1. →Putting n=1.

→7(1)-5

→7-5

→2

${\boxed{\boxed{→First\:Term=2✔}}}$

2. →Putting n=2.

→7(2)-5

→14-5

→9

${\boxed{\boxed{→Second\:Term=9✔}}}$

3. →Putting n=3.

→7(3)-5

→21-5

→16

${\boxed{\boxed{→Third\:Term=16✔}}}$

4. →Putting n=4.

→7(4)-5

→28-5

→23

${\boxed{\boxed{→Fourth\:Term=23✔}}}$

☞So the first four terms of the A.P are→2,9,16,23 and so on respectively.And the A.P is 2,9,16,23,..........

HOPE IT HELPS.