Computer Science, asked by fathimajogee3802, 10 months ago

What is the first valid host on the subnetwork that the node 192.168.69.171 255.255.255.128 belongs to?

Answers

Answered by Brainercape9
0

Found using iPv4/iPv4 calculator, just so you know

Address:   192.168.69.171        11000000.10101000.01000101 .10101011

Netmask:   255.255.255.0 = 24    11111111.11111111.11111111 .00000000

Wildcard:  0.0.0.255             00000000.00000000.00000000 .11111111

=>

Network:   192.168.69.0/24       11000000.10101000.01000101 .00000000 (Class C)

Broadcast: 192.168.69.255        11000000.10101000.01000101 .11111111

HostMin:   192.168.69.1          11000000.10101000.01000101 .00000001

HostMax:   192.168.69.254        11000000.10101000.01000101 .11111110

Hosts/Net: 254                   (Private Internet)

Subnets

Netmask:   255.255.255.128 = 25  11111111.11111111.11111111.1 0000000

Wildcard:  0.0.0.127             00000000.00000000.00000000.0 1111111

Network:   192.168.69.0/25       11000000.10101000.01000101.0 0000000 (Class C)

Broadcast: 192.168.69.127        11000000.10101000.01000101.0 1111111

HostMin:   192.168.69.1          11000000.10101000.01000101.0 0000001

HostMax:   192.168.69.126        11000000.10101000.01000101.0 1111110

Hosts/Net: 126                   (Private Internet)

Network:   192.168.69.128/25     11000000.10101000.01000101.1 0000000 (Class C)

Broadcast: 192.168.69.255        11000000.10101000.01000101.1 1111111

HostMin:   192.168.69.129        11000000.10101000.01000101.1 0000001

HostMax:   192.168.69.254        11000000.10101000.01000101.1 1111110

Hosts/Net: 126                   (Private Internet)

Subnets:   2  

Hosts:     252

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