what is the flux due to electric field E = 3 x 103 i N/C through a square of side 10cm , when it is held normal to E .
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Electric field intensity = 3 × 10³ î N/C
magnitude of electric field intensity = 3 × 10³ N/C
Side of the square, s = 10 cm = 0.1 m
Area of the square, A = s² = 0.01 m²
The plane of the square is parallel to the y-z plane.
Hence, angle between the unit vector normal to the plane and electric field will be θ = 0°
Flux (Φ) through the plane by the relation
Φ = EA cos θ
= 3 × 10³ × 0.01 × cos0°
= 0.03 × 10³
= 30 N m²/C
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