Question

what is the flux due to electric field E = 3 x 10³ i N/C through a square of side 10cm , when it is held normal to E .​

Answer 1

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GIVEN

• Electric field ( E) = 3 x 10³ i N/C

• The flux through a square whose side (a) = 10 cm.

FORMULA

• Flux ( Φ ) = E A

where,

• E = Electric field

• A = Area

SOLUTION

• The side of square = 10 cm = 0.1 m

So

• The area of one side of square =

${a}^{2} = {(0.1)}^{2} = 0.01 \: { m}^{2}$

Now Flux =

$E A = 3 \times {10}^{3} \times 0.01 = 30 \: N {m}^{2} {c}^{ - 1}$