Question

What is the flux through the plane taken perpendicular to the field?
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Answer 1

Answer:

The flux through the plane taken perpendicular to the field is E.A.

Explanation:

First, let's see how flux is calculated. i.e.

$\phi=E.A=EA cos\theta$        (1)

Where,

Ф=flux through the plane

E=elctric field through-plane

A=area of the plane

θ=angle between electric field and area vector of the plane

If the electric field will be perpendicular to the plane then the area vector will be parallel to the plane. That means that the angle between the electric field vector and area vector will be 0°.

By substituting the value of "θ" in equation (1) we get;

$\phi=EA cos0\textdegree$            (cos0°=1)

$\phi=E.A$

Hence, the flux through the plane taken perpendicular to the field is E.A.

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Answer 2

Answer:

The flux through the plane taken perpendicular to the field stands E.A.

Explanation:

The flux through the plane taken perpendicular to the field stands E.A.

Explanation:

First, let's notice how flux is computed. i.e.

$\phi=E \cdot A=E A \cos \theta$

Where,

$\Phi=$ flux through the plane

$E=$ electric field through-plane

$A=a r e a$of the plane

If the electric field will be perpendicular to the plane then the area vector will be parallel to the plane. That indicates that the angle between the electric field vector and area vector will be $0^{\circ}$.

By replacing the value  in equation (1) we get;

$&\phi=E A \cos 0^{\circ}$

$\quad\left(\cos 0^{\circ}=1\right)$

$&\phi=E \cdot A$

Thus, the flux through the plane carried perpendicular to the field is E.A.

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